How to Solve BODMAS Questions and Simplification Questions
BODMAS is a rule that tells us the correct order to solve math problems with multiple operations. If we don’t follow BODMAS, we might get the wrong answer.
BODMAS Rule
- Brackets → Solve inside
( )
,{ }
,[ ]
first. - Orders → Solve powers (
², ³
) and roots (√
). - Division & Multiplication → Left to right.
- Addition & Subtraction → Left to right.
Examples of BODMAS Simplification
Example 1: Nested Brackets
Problem:12 + {6 − [3 × (4 − 2)]} ÷ 2
Solution:
- Innermost bracket: (4 − 2) = 2
→ 12 + {6 − [3 × 2]} ÷ 2 - Next bracket:
[3 × 2] = 6
→12 + {6 − 6} ÷ 2
- Curly bracket: {6 − 6} = 0
→12 + 0 ÷ 2
- Division:
0 ÷ 2 = 0
- Addition:
12 + 0 = 12
Final Answer: 12
Example 2: Powers and Division
Problem:(5² − 4 × 3) ÷ (6 − 2²)
Solution:
- Solve powers first:
5² = 25
2² = 4
→(25 − 4 × 3) ÷ (6 − 4)
- Multiplication inside bracket:
4 × 3 = 12
→(25 − 12) ÷ (6 − 4)
- Subtraction inside brackets:
25 − 12 = 13
6 − 4 = 2
→13 ÷ 2
- Division:
13 ÷ 2 = 6.5
Final Answer: 6.5
Example 3: Mixed Operations with Fractions
Problem:8 ÷ 2 × (2 + 2) − 4² ÷ 4
Solution:
- Bracket first:
(2 + 2) = 4
→8 ÷ 2 × 4 − 4² ÷ 4
- Power (Order):
4² = 16
→8 ÷ 2 × 4 − 16 ÷ 4
- Division & Multiplication (left to right):
8 ÷ 2 = 4
4 × 4 = 16
16 ÷ 4 = 4
→16 − 4
Subtraction: 16 − 4 = 12
Final Answer: 12
Example 4: Complex Nested Brackets
Problem:20 − [5 + {8 − (3 × 2)}] × 2
Solution:
- Innermost bracket:
(3 × 2) = 6
→20 − [5 + {8 − 6}] × 2
- Curly bracket:
{8 − 6} = 2
→20 − [5 + 2] × 2
- Square bracket:
[5 + 2] = 7
→20 − 7 × 2
- Multiplication:
7 × 2 = 14
- Subtraction:
20 − 14 = 6
Final Answer: 6
Key Tips for BODMAS Simplification Rule
1.Always start from the innermost bracket.
2.Solve powers/roots before ×, ÷, +, −.
3.If same priority (like × & ÷), solve left to right.
4.Double-check calculations to avoid mistakes.
BODMAS question from easy to hard level
- 5 + 3 × 2
- 10 – 4 ÷ 2
- (6 + 2) × 3
- 8 ÷ 4 + 1
- 12 – (5 + 2)
- 3 + 4 × (5 – 2)
- 2³ + 4 × 2
- (7 – 2) × (3 + 1)
- 10 ÷ (2 + 3)
- 5 × 2² – 6
- 15 – 3 × 4 + 2
- 6 ÷ 2 + 4 × 3
- (9 – 5) × 2 + 7
- 3 + 12 ÷ (4 – 1)
- 2 × (5 + 3) – 4
- 2 + [3 × (4 + 1)]
- (2³ + 4) × (5 – 2)
- 5 × [6 – (3 + 1)]
- 12 ÷ {3 × (2 – 1)}
- 8 + (5 × 2²) ÷ 2
- (10 – 2 × 3) ÷ 4
- 3 + (6 × 2) ÷ 4
- (5 × 2) + 12 ÷ 3 – 1
- (8 – 2) × 3 ÷ 6
- 4² – (10 + 6) ÷ 2
- {5 + [3 × (6 – 2)]} ÷ 4
- 2⁴ – (3 × 2) + 12 ÷ 3
- (10 ÷ 2) + [4 × (3 – 1)²]
- 20 – {3 × [5 – (2 + 1)]}
- (4 + 6) × 2 ÷ 5 + 3²
- 3 × (4 + 2³) – 5
- (12 ÷ 3)² + 5 × 2
- 7 + [18 ÷ (6 – 3)] ÷ 2
- 5² – [4 × (6 – 2) + 1]
- (9 – 5) × 3 ÷ 2 + 4²
- A shop has 12 chocolates. If 3 kids buy 2 chocolates each, how many are left? (Write as BODMAS: 12 – 3 × 2)
- A box has 5 rows of 4 apples. If 6 apples are removed, how many remain? (BODMAS: 5 × 4 – 6)
- A man buys 3 packs of 6 pens and gives away 4. How many pens does he have? (BODMAS: 3 × 6 – 4)
- If a pizza is cut into 8 slices and 3 people eat 2 slices each, how many are left? (BODMAS: 8 – 3 × 2)
- A classroom has 30 seats. If 4 rows have 5 seats each and the rest are single, how many single seats are there? (BODMAS: 30 – 4 × 5)
- (2 + 3²) × (4 – 1)
- 5 + [16 ÷ (8 – 4)] ÷ 2
- 3 × [5 + (6 – 2)²]
- (7 × 2) + 18 ÷ 3² – 1
- 10 – {2 × [3 + (5 – 2)]}
- (5 + 3) × 2 ÷ 4 + 6
- 2³ × (4 – 1) + 5
- (9 ÷ 3) + [2 × (5 – 1)²]
- 25 – {4 × [6 – (3 + 1)]}
- (12 – 4) × 3 ÷ 6 + 2
BODMAS Question with answer
How to Solve BODMAS questions ? Below is the answers just click below
BODMAS questions and answer
- 5 + 3 × 2 = 11
- 10 – 4 ÷ 2 = 8
- (6 + 2) × 3 = 24
- 8 ÷ 4 + 1 = 3
- 12 – (5 + 2) = 5
- 3 + 4 × (5 – 2) = 15
- 2³ + 4 × 2 = 16
- (7 – 2) × (3 + 1) = 20
- 10 ÷ (2 + 3) = 2
- 5 × 2² – 6 = 14
- 15 – 3 × 4 + 2 = 5
- 6 ÷ 2 + 4 × 3 = 15
- (9 – 5) × 2 + 7 = 15
- 3 + 12 ÷ (4 – 1) = 7
- 2 × (5 + 3) – 4 = 12
- 2 + [3 × (4 + 1)] = 17
- (2³ + 4) × (5 – 2) = 36
- 5 × [6 – (3 + 1)] = 10
- 12 ÷ {3 × (2 – 1)} = 4
- 8 + (5 × 2²) ÷ 2 = 18
- (10 – 2 × 3) ÷ 4 = 1
- 3 + (6 × 2) ÷ 4 = 6
- (5 × 2) + 12 ÷ 3 – 1 = 13
- (8 – 2) × 3 ÷ 6 = 3
- 4² – (10 + 6) ÷ 2 = 8
- {5 + [3 × (6 – 2)]} ÷ 4 = 4.25
- 2⁴ – (3 × 2) + 12 ÷ 3 = 14
- (10 ÷ 2) + [4 × (3 – 1)²] = 21
- 20 – {3 × [5 – (2 + 1)]} = 14
- (4 + 6) × 2 ÷ 5 + 3² = 13
- 3 × (4 + 2³) – 5 = 31
- (12 ÷ 3)² + 5 × 2 = 26
- 7 + [18 ÷ (6 – 3)] ÷ 2 = 10
- 5² – [4 × (6 – 2) + 1] = 8
- (9 – 5) × 3 ÷ 2 + 4² = 22
- 12 – 3 × 2 = 6
- 5 × 4 – 6 = 14
- 3 × 6 – 4 = 14
- 8 – 3 × 2 = 2
- 30 – 4 × 5 = 10
- (2 + 3²) × (4 – 1) = 33
- 5 + [16 ÷ (8 – 4)] ÷ 2 = 7
- 3 × [5 + (6 – 2)²] = 63
- (7 × 2) + 18 ÷ 3² – 1 = 15
- 10 – {2 × [3 + (5 – 2)]} = 4
- (5 + 3) × 2 ÷ 4 + 6 = 10
- 2³ × (4 – 1) + 5 = 29
- (9 ÷ 3) + [2 × (5 – 1)²] = 35
- 25 – {4 × [6 – (3 + 1)]} = 17
- (12 – 4) × 3 ÷ 6 + 2³ = 12
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